UPSC ESIC Recruitment 2024
Union Public Service Commission (UPSC), Employees’ State Insurance Corporation, ESIC has issued a notification for recruitment of Nursing Officer post. A total of 1930 vacancies are to be filled through this recruitment. UPSC ESIC Recruitment 2024.
एकूण जागा : 1930
पदाचे नाव :
नर्सिंग अधिकारी
शैक्षणिक पात्रता :
(i) B.Sc. (Hons.) Nursing किंवा (i) B.Sc. (Nursing)
(ii) राज्य नर्सिंग सह नोंदणी
किंवा
(i) GNM +01 वर्ष अनुभव
(ii) राज्य नर्सिंग सह नोंदणी
वयाची अट : 27 मार्च 2024 रोजी,
खुला गट: 18 ते 30 वर्ष
SC/ST: 05 वर्षे सूट
OBC: 03 वर्षे सूट
फी :
General/OBC: 25/-
SC/ST/PwD/महिला: फी नाही
अर्ज करण्यास सुरुवात :
07 मार्च, 2024
अर्ज करण्याची शेवटची तारीख :
27 मार्च, 2024
अधिकृत संकेतस्थळ : Website
जाहिरात : Click Here
Online अर्ज : Click Here
Total Vacancies : 1930
Post Name :
Nursing Officer
Educational Qualification :
(A) (i) A Bachelor of Science (Honours) degree in Nursing from a recognised University or Institute; or completion of a regular course in Bachelor of Science in Nursing from a recognised University or Institute, or completion of a Post Basic Bachelor of Science in Nursing from a recognised University or Institute; and (ii) Registration as a nurse or nurse and midwife (registered Nurse or registered Nurse & registered Midwife) with the State Nursing council.
OR
(B) (i) Possession of a Diploma in General Nursing Midwifery from a recognised Board of Council; (ii) Registration as a nurse or nurse and midwife (registered Nurse or registered Nurse & registered Midwife) with the State Nursing Council; (iii) Minimum one year of experience in a hospital with a minimum of fifty beds after obtaining the educational qualification
Age Limit : As on 27 March 2024,
Open Category: 18 to 30 Years
OBC: 3 Years Relaxation
SC/ST: 5 Years Relaxation
Fees :
General/OBC: 25/-
SC/ST/PwD/Female: No Fees
Application Start Date :
07 March, 2024
Last Date To Apply :
27 March, 2024
Official Website : Website
Notification : Click Here
Apply Online : Click Here